VINAY SHARMA BIG B OF PHYSICS NEET JEE

HC Verma Solutions – Concepts of Physics Part 1 – Chapter 1 Objective II HC Verma Solutions – Concepts of Physics Part 1 Chapter 1: Introduction to Physics – Objective II Q1. The dimensions ML⁻¹T⁻² may correspond to: (a) work done by a force (b) linear momentum (c) pressure (d) energy per unit volume Answer: (c), (d) Solution: Work done/energy = Force × distance = [MLT⁻²][L] = [ML²T⁻²] → does not match. Linear momentum = mass × velocity = [M][LT⁻¹] = [MLT⁻¹] → does not match. Pressure = Force / Area = [MLT⁻²] / [L²] = [ML⁻¹T⁻²] → correct. Energy per unit volume = [ML²T⁻²] / [L³] = [ML⁻¹T⁻²] → correct. Q2. Choose the correct statement(s): (a) A dimensionally correct equation may be correct. (b) A dimensionally correct equation may be incorrect. (c) A dimensionally incorrect equation may be correct. (d) A dimensionally incorrect equation may be incorrect. Answer: (a), (b...

HC Verma Solutions – Concepts of Physics Part 1 – Chapter 1 HC Verma Solutions – Concepts of Physics Part 1 Chapter 1: Introduction to Physics – Objective I Q1. Which of the following sets cannot enter into the list of fundamental quantities in any system of units? (a) length, mass, and velocity (b) length, time and velocity (c) mass, time and velocity (d) length, time and mass Answer: (b) Solution: Fundamental quantities must be independent of each other. In option (b), velocity depends on length and time ( v = L/T ), so it cannot be chosen as a fundamental quantity. Also, without mass the system is incomplete. Hence option (b) is invalid. Q2. A physical quantity is written as n·u, where u is the unit and n is the numerical value. If the same quantity is expressed in different units, then (a) n ∝ u (b) n ∝ u² (c) n ∝ √u (d) n ∝ 1/u Answer: (d) Solution: For any physical quantity, the prod...